sql - How to increment column regard on another column value -


i have following data:

(1,'20120615 8:03:43 pm'), (1,'20120615 8:03:43 pm'), (1,'20120615 8:03:48 pm'), (1,'20120615 8:03:53 pm'), (0,'20120615 8:03:58 pm'), (1,'20120615 8:04:03 pm'), (1,'20120615 8:04:08 pm'), (1,'20120615 8:04:13 pm'), (1,'20120615 8:04:18 pm'), (0,'20120615 8:04:23 pm'), (1,'20120615 8:04:28 pm'), (1,'20120615 8:04:33 pm');

my desired result is:

(1,'20120615 8:03:43 pm', 1), (1,'20120615 8:03:43 pm', 1), (1,'20120615 8:03:48 pm', 1), (1,'20120615 8:03:53 pm', 1), (0,'20120615 8:03:58 pm', 0), (1,'20120615 8:04:03 pm', 2), (1,'20120615 8:04:08 pm', 2), (1,'20120615 8:04:13 pm', 2), (1,'20120615 8:04:18 pm', 2), (0,'20120615 8:04:23 pm', 0), (1,'20120615 8:04:28 pm', 3), (1,'20120615 8:04:33 pm', 3);

in words want group data except 0 above order.

here idea. create flag each group starts. 1 - col1 in data above. take cumulative sum of flag. values not 0, group. following query takes approach, using correlated subqueries computation:

select t.col1, t.dt,        (case when t.col1 = 0 0 else 1+grouping end) (select t.*,              (select sum(1-col1)               t t2               t2.dt <= t.dt              ) grouping       t      ) t;

in sql server 2012, can cumulative sum:

select t.col1, t.dt,        (case when col1 = 0 0              else 1+sum(1 - col1) on (order dt)         end) t;

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