Generating a random number within range of 0-9 in x86 8086 Assembly -


first of all, new 8086 assembly , has been pretty difficult me grab knowledge. nevertheless, i'll best.

i have been trying write code generate random number within range of 0-9. after looking several examples , suggestion, ended with. did not apply mathematical function on retrieved clock count, simplicity , thought unnecessary. ended with, reasons, generating number 6,7 fewer times numbers such 1,3 , 9. believe because i'm taking lower order of clock ticks, values change rapidly.

my purpose simulate dice roll later ill change range of below codes 1-6. question is, adequate enough purpose? or there better way this?

codes:

randgen:        ; generate rand no using system time randstart:    mov ah, 00h  ; interrupts system time            int 1ah      ; cx:dx hold number of clock ticks since midnight                       ; lets take lower bits of dl start..    mov bh, 57   ; set limit 57 (ascii 9)     mov ah, dl      cmp ah, bh   ; compare value in  dl,          ja randstart ; if more, regenerate. if not, continue...      mov bh, 49   ; set limit 48 (ascii 0)    mov ah, dl       cmp ah, bh   ; compare value in dl    jb randstart ; if less, regenerate.         ; if not, need     mov ah, 2h   ; call interrupt display value in dl    int 21h     ret

answer, @johnfound:

i found way simpler, , takes less time generate random number. mentioned works if need 1 single random numbers, or interval between random numbers includes pauses human input. if not, numbers not random @ (i believe due time seed take doesn't change). fine case, since simulating roll dice, , need user intervention (another roll) before running code again.

randgen:         ; generate rand no using system time randstart:    mov ah, 00h  ; interrupts system time            int 1ah      ; cx:dx hold number of clock ticks since midnight           mov  ax, dx    xor  dx, dx    mov  cx, 10        div  cx       ; here dx contains remainder of division - 0 9     add  dl, '0'  ; ascii '0' '9'    mov ah, 2h   ; call interrupt display value in dl    int 21h     ret

what did: 1.we moved value in dx ax 2.we cleared dx. 3.we moved 10 dec cx. 4.we divided ax cx hence remainder within 0-9 dec stored in dx 5.finally, added ascii '0' (dec 48) dx them ascii '0' '9'.

this trick works if need 1 single random numbers, or interval between random numbers includes pauses human input. in other cases, numbers not random @ all.

if need many random numbers, there different pseudo-random number algorithms available.

another note there more easy way number in needed interval:

    mov  ax, dx     xor  dx, dx     mov  cx, 10         div  cx       ; here dx contains remainder of division - 0 9      add  dl, '0'  ; ascii '0' '9'

you can use method every random number generator of course.


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