How to evaluate the following c program? -

#include<stdio.h>   int main() {   int x;   x=~!printf;   printf("%x",x); } 

can 1 explain me process derive output of program.

• printf pointer printf function - it's integer of sort.
• ! unary not, meaning returns 0 if operand true, , 1 operand false. since printf true (non-zero, because function defined), subexpression far 0.
• ~ bitwise complement. flips bits of binary number given. since given 0, return 0xffffffff.
• that result stored x , printed out in hexadecimal.

on 64-bit machine might instead 0xffffffffffffffff, though i'm not entirely certain.