loops - Python - most efficient way of matching a list -


say example have list of 7 numbers, let's call 'linea' , have 50 lines of numbers below , want see if 'linea' matches 50 lines in order. quickest (time-wise)/most efficient way of doing it? loop? or other method?

linea = [1,2,3,4,5,6,7]  linetwo = [1,33,40,44,45,1,2] linethree = [2,13,22,41,50,8,9] linefour = [1,2,3,4,5,6,7] linefive = etc.....(repeat 50 times)

thank you

you can compare 2 lists == operator:

if linea == lineone:     print 'they match!'

now, keep lines in list:

lines = [lineone, linetwo, linethree, ..., linefifty]

and find lines match:

matches = [line line in lines if line == linea]

you can't more efficient comparing each line (o(n)). unless sort input first. use bisect module , o(log n) performance. if want compare lineb, linec, linez lines well. otherwise don't bother, because sorting compare lines o(n * log n)...


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