bash - List all directories not containing a subdirectoriy -


i have solution question

find . -type d -exec sh -c 'test $(find "$0" -maxdepth 1 -type d | wc -l) -eq 1' {} \; -print

i wonder, whether there better (faster) method this. don't start in 'find' find process.

with little more coding following commandshould work:

find . -type d|awk 'nr>1{a[c++]=$0; t=t $0 subsep} end{for (i in a) {if (index(t, a[i] "/") > 0) delete a[i]} (i in a) print a[i]}'

making more readable:

find . -type d | awk 'nr > 1 {    a[c++]=$0;    t=t $0 subsep } end {    (i in a) {       if (index(t, a[i] "/") > 0)          delete a[i]}    (i in a)       print a[i] }'

while might more coding in solution in big directory awk based command should run faster embedded find | wc solution, in question.

performance testing:

i ran on directory containing 15k+ nested sub directories , found awk command considerably faster (250-300% faster) op's find | wc command.


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