How to take path from variable Bash -


this question has answer here:

i can't path variable in bash. how correct? example:

my@pc:~$ a="~/.bashrc" my@pc:~$ cat $a cat: ~/.bashrc: no such file or directory

didn't work, but

cat .bashrc

and

cat ".bashrc"

works well.

here right answer fedorqui

cat $(eval echo $a)

the reason issue tilde expanded home directory shell. when store in variable, tilde not expanded , cat looks file .bashrc in folder ~ (rather home directory)

there 2 ways around issue: proposed eval, , using $home:

a="$home/.bashrc"

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