python - "execfile" doesn't work properly -


i'm trying make launcher python program tkinter. used execfile function, , fortunately opened target gui. however, none of buttons work, , global variable functions reference isn't defined.

the code launch program:

def launch():     execfile("gui.py")

that works. base code target program:

from tkinter import * gui = tk() gui.title("this gui")

edit: example of button:

def buttonwin():     buttonwindow = toplevel(gui)     button = button(buttonwindow, text = "button", width = 10, command = none)     button.pack()

when references 'gui' variable toplevel, comes error. tried defining 'gui' variable in launcher script, caused target script open first, instead of launcher:

gui = tk() launcher = tk() launcher.title("launcher") def launch():     return execfile("gui.py") launchbutton = button(launcher, text = "launch", width = 10, command = launch)

when try pressing 1 of program's buttons, nameerror: $nameerror: global variable 'gui' not defined$ in python 2.7.5. thank answers, , sorry errors code blocks; i'm new.

the problem have structured tkinter program incorrectly.

in "gui.py" should have like:

from tkinter import *  gui= tk() gui.mainloop()

you can add buttons perform functions , customize it:

from tkinter import *  gui = tk() gui.title("this gui")      def launch():     execfile("gui.py")  launchbutton = button(gui, text='launch program', command=launch) launchbutton.pack()  gui.mainloop()

i think function buttonwin trying handled class; see unutbu's answer here.

i'm not sure if i've addressed problem, should start.


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