java - Why is my program only letting me input one value after the first iteration of the for loop? -

this question has answer here:

• scanner skipping nextline() after using next(), nextint() or other nextfoo()? 12 answers

i extremely new java programming , trying make poker hand evaluator. asking suit , value of card, using loop. reason, works first iteration of loop asks me 1 value after that. here code:

import java.util.scanner; public class pokerrun {  public static void main(string[] args) {      int [] suit = new int[5];     int [] value = new int[20];     card card1 = new card();     scanner in = new scanner(system.in);     int counter = 1;     system.out.println("welcome poker hand evaluator!");     for(int = 1; i<6; i++)     {         system.out.println("what suit of card " + + "?\nplease type suit in lowercase letters: ");         card1.suit = in.nextline();         system.out.println("what value of card " + + "?  (j = 11, q = 12 k = 13, = 14");         card1.value = in.nextint();         //checks if face card, if true, changes card.facecard         if(card1.value == 11)             card1.facecard = "jack";         else if(card1.value == 12)             card1.facecard = "queen";         else if(card1.value == 13)             card1.facecard = "king";         else if(card1.value == 12)             card1.facecard = "ace";          if(card1.value<11)             system.out.println("you entered " + card1.value + " of " + card1.suit + ".");         else             system.out.println("you entered " + card1.facecard + " of " + card1.suit + ".");     }  }  } 

rohit jain, yes problem.

my suggestion solution exchange line

card1.value = in.nextint();

with:

card1.value= integer.parseint(in.nextline());

this should work you.

to explain bit more scanner build string parsing of files etc. , not commandline inputs. use bufferedreader:

bufferedreader reader = new bufferedreader(new inputstreamreader(system.in)); reader.readline();